Test the claim that : < 80 for these data using = 0.10:
60 
70 
75 
55 
80 
55 
65 
40 
80 
70 
80 
95 
120 
90 
75 
85 
80 
60 
Note that is 80.
First enter the data in by pressing STAT and selecting 1:Edit by pressing ENTER. The result is shown below
Press STAT, then RIGHT ARROW twice to TESTS. Press 2 to select 2:TTest. If Data is not already highlighted, LEFT ARROW to highlight it, and then press ENTER to select the data mode. ARROW DOWN once and enter 80 next to :. Make sure the defaults of for List: and 1 for Freq: are also listed.



ARROW DOWN to :. Use the arrow keys to highlight <, since the claim being tested is < 80, and press ENTER. ARROW DOWN to select Calculate, and then press ENTER. The results are shown below.
Conclusions based on tvalue:
The test t value shown above is t = 1.381. Using a t distribution
table for a 1tailed test with=
0.10 and d.f.= 17, we find that the critical t value is t =
1.333.
This is a lefttailed
test, so since 1.381 < 1.333, we are in the rejection region, so
reject :
80, and accept the alternative hypothesis :<
80.
Conclusions based on Pvalue:
The test p value shown above is p = 0.0926361139. The decision is to reject
: 80, since 0.0926361139 < 0.10; that is, p < .
Test the claim : = 8 when = 0.6, = 8.2, and n = 25 using = 0.05. We use : 8.
Press STAT, then RIGHT ARROW twice to TESTS. Press 2 to select 2:TTest.



If STATS is not highlighted, ARROW RIGHT once and press ENTER to select STATS. ARROW DOWN once and enter the value of 8 for . ARROW DOWN once and enter 8.2 for . ARROW DOWN once and enter .6 for . ARROW DOWN once again, and enter 25 for n.
Now we must choose which test. Since this is a twotailed test, ARROW DOWN once to : then use the LEFT or RIGHT ARROW to select , then press ENTER. ARROW DOWN one last time to Calculate and then press ENTER. The results are shown below.


Conclusions based on tvalue:
The test t value shown above is t = 1.667. Using a tdistribution table
for =
0.05, d.f.= 24 and the fact that this is a twotailed test, we find that
the critical value is t = 2.064. Thus, the rejection region is t <
2.064 or t > 2.064. Since 2.064 < 1.667 < 2.064, the
decision is that we cannot reject :
= 8.
Conclusions based
on Pvalue:
The test p value shown about is p = 0.1085801058. Thus, we cannot reject
:
= 8 since 0.1085801058 > 0.05